Write a function in C++ which accepts an integer array and its size as arguments / parameters and assign the elements into a two dimensional array of integers in the following format:

                                                                         CBSE 2006

If the array is 1 2 3 4 5 6

The resultant 2 D array is given below

1 2 3 4 5 6

1 2 3 4 5 0

1 2 3 4 0 0

1 2 3 0 0 0

1 2 0 0 0 0

1 0 0 0 0 0

If the array is 1 2 3

The resultant 2 D array is given below

1 2 3

1 2 0

1 0 0

#include<iostream.h>

#include<conio.h>

void form_matrix(int ar[], int m)

{

// forming the matrix 

int mat[m][m];

int max = m;

int min = 1;

for(int i = 0; i < m ; i++)

{

min= 1;

for(int j = 0; j < m ; j++, min++)

{

if(min < = max )

   mat[i][j] = min;

else

   mat[i][j] = 0;

}

max--;

}

cout<<" \n The matrix :";

// Displaying the matrix

for( i = 0 ; i < m; i++)

{

cout << "\n ";

for( j = 0 ; j< m ; j++)

cout << mat[i][j] << " ";

}

}

void main()

{

int m[10], sz, i, j;

cout<< " \n What is the size of an array ?";

cin >>  sz;

/* for inputing the  elements.....*/

for( i = 0 ; i < sz; i++)

m[i] = i+1;

cout << "\n The array ";

/* display array */

for( i = 0; i < sz ; i++)

cout<< m[i];

 /* call the function */

form_matrix(m, sz);

getch();

}

Write a function REASSIGN() in c++ , which accepts an array of integers and its size as parameters and divide all those array elements by 5 which are divisible by 5 and multiply other array elements by 2

CBSE 2010

#include<iostream.h>

#include<conio.h>

void REASSIGN(int a[], int size)

{

for(int i = 0 ; i < size ; i++)

{

if(a[i]%5 == 0)

  a[i] = a[i] / 5;

else 

   a[i] = a[i] * 2;

}

void main()

{

int arr[25];

int n, i;

cout << "\n Enter the size of an array (<25):":

cin >> n;

for( i = 0 ; i < n ; i++)

{cout<< "\n Enter an element :";

cin >> arr[i];

}

/* Display original array */

cout<< "\n The Original array :";

for(i = 0 ; i < n ; i++)

cout<< arr[i] << " ";

REASSIGN(arr, n);

cout<< "\n The changed array :";

/* Display the changed array */

for(i = 0 ; i < n ; i++)

cout<< arr[i] << " ";

getch();

}

Write a function int ALTERSUM( int B[][5] , int N, int M) in c++ to find and return the sum of elements from all alternate elements of a two-dimensional array starting from B[0][0].

Hint: If the following is the content of the array

4 5 1

2 8 7

9 6 3

The function should add elements B[0][0], B[0][2], B[1][1], B[2][0], B[2][2]

CBSE 2010

#include<iostream.h>

#include<conio.h>

#define x 10

#define y 5

int ALTERSUM(int B[][5], int M, int N)

{

int flag = 0, sum = 0;

for(int i = 0 ; i < M ; i++)

for(int j = 0 ; j < N ; j++)

{

if(flag == 0)

{ 

   sum = sum + B[i][j];

   flag = 1;

}

else

   flag = 0;

}

return sum;

}

void main()

{

int arr[x][y], r, c, i , j;

cout << "\n How many rows(<10)? " ;

cin >> r;

cout << "\n How many cols(< 5)?";

cin >> c;

/* Input elements */

for( i = 0 ; i < r ; i++)

for(j = 0 ; j< c ; j++)

{

cout << "\n Enter elements :";

cin >> arr[i][j];

}

/* display matrix */

for(i = 0; i < r  ; i++)

for(j = 0; j < c ; j ++)

    cout << arr[i][j] << " ";

cout<< endl;

int sum = ALTERSUM(arr, r, c);

cout << "\n The Sum of alternate elements = " << sum;

getch();

}

Write a function in C++ to print the product of each column of a two dimensional integer array passed as the argument of the function.

                                                    CBSE 2008

Explain : If the two dimensional array contains

         1     2     4

         3     5     6

         4     3     2

         2     1     5

The output should appear as :

Product of Column 1 = 24

Product of Column 2 = 30

Product of Column 3 = 240

                                                                                             

#include<iostream.h>

#include<conio.h>

#define r 10

# define c 10

void ProCol(int a[][], int m , int n) 

// n represents column

// m represents row

{

int pro[n], i, j ;

for(i = 0; i  <  n ; i++)

{

pro[i] = 1;

for(j = 0 ; j  <  m ; j ++)

{

pro[i] = pro[i] * a[j][i];

}

cout << "\n Product of Column 1 : " <<  pro[i];

}

}

void main()

{

int arr[r][c];

int row, col, i, j;

// Input dimension ~

cout <<  "\n Enter row & Column :";

cin >>  row >>  col ;

// Input elements for the array ~

for( i = 0; i <  row ; i++)

for ( j = 0 ; j <  col ; j++)

{

cout << "\n Enter the element for position : "   << i+1 << " , " <<  j+1 ;

cin >>  arr[i][j];

}

// Display the array

for( i = 0;  i < row ; i++ )

{

for( j =0 ; j < col ; j ++)

    cout   <<  arr[i][j]   <<  "  ";

cout  <<   endl;

}

// Calling the function

ProCol(arr, row, col);

getch();

}

Define a function SWAPCOL() in C++ to swap (interchange) the first column elements with the last column elements, for a two dimensional integer array passed as the argument of the function.

Example : If the two dimensional array contains 

       2   1   4   9

       1   3   7   7 

       5   8   6   3

       7   2   1   2

After swapping of the content of 1st column and the last column, it should be :

      9   1   4   2

      7   3   7   1

      3   8   6   5

      2   2   1   7                                (CBSE 2009)

#include<iostream.h>

#include<conio.h>

void swapcol(int a[][], int r, int c)
   // r -> row, c ->col

{ int t;

for(int i = 0; i< r ; i++)

{

t = a[i][0];

a[i][0] = a[i][c-1];

a[i][c-1] = t;

}

}

void main()

{

int arr[10][10];

int m, n, i, j;

cout<<"\n Enter rows & columns :";

int m, n;

cin >> m >> n;

/* Input Array Elements */

for ( i = 0; i< m ; i++)

for( j = 0; j < n ; j++)

{

cout<< "\n Enter element for the array[ " << i+1 << " ] "<< " [ " << j+i << "]" ;

cin >> arr[i][j];

}

/* Swap function call */

swapcol(arr, m, n);

/* Display Array in Matrix form */

for( i = 0; i < m ; << i ++)

{ cout<< endl;

for (  j = 0; j < n ; j ++)

cout << arr[i][j] << "  ";

}

getch();

}

Declare a class to represent fixed-deposit account of 10 customers with the following data members: Name of the depositor, Account Number, Time Period ( 1 or 3 or 5 yrs), Amount. The class also contains following member functions : (A) To initialise data members. , (B) For withdrawal of money (after half or the time period has passed ). , (C) To display the data members. Write a program to handle 10 account holders. Make necessary changes in the class definition - if required.

#include<iostream.h>

#include<conio.h>

#include<string.h>

#include<stdio.h>

class account

{

private:

char name[20];

long acno;

int time;

double amount;

public :

void get_data( char nm[], long n, double am)

{

strcpy(name, nm);

acno = n;

time  = 1;

cout<< "\n Enter Duration ( for 3 yrs / 5 yrs) ..... \n else duration will be considered as 1 yr. ";
int t;
cin>> t;
if(t == 3 || t == 5)
  time = t;

amount = am;

}

void withdrw()

{

cout<< "\n Enter the time period,that has passed after creating new fixed-deposit A/c :"

int a;
cin>>a;

cout<< "\n The amount to be drawn :";

double d;

cin>>d;

if(a > = time/2)

   {

    if(d <= amount) 

         amount = amount - d;

     else

         cout<<"\n Balance is less in your account.Abort !";

    }

else

         cout<<"\n Money can not be withdrawn. For details contact helpline.";

}

void display()

{

cout<< "A/C No." << "\t" << "Name " << "\t\t" << "Amount" << "\n\n";

cout << acno << "\t" << name << "\t\t" << amount << "\n\n";

}

void display_time()

{

cout<< "\n A/c Duration = " << time << "yrs";

}

};

void main()

{

account customer[10];

char ch= 'y';

char nam[20];

long acn;

double amt;

/* Input 10 customer's details  */

for(int i = 0; i < 10 ; i++)

{

cout<< "\n Do you want to create a new account. Minimum duration is 1 yr":

cout<< "Enter (y /n) :";

cin >> ch;

if(tolower(ch) ! = 'y')
          { i--;

            continue;
          }

cout<< "\n Enter name :";

gets(nam) ;

cout<< "\n Enter A/c No. ";

cin>> acn;

cout<< "\n Enter amount ";

cin>> amt;

customer[i].get_data(nam, acn, amt);

}

/* Display 10 customer's details */

for(i = 0; i<10; i++)

{

customer[i].display();

}

/* withdraw money */

cout<< "\n************** Do you Withdraw Money ........\n";

cout<< "\n You can withdraw money only when, after creating your A/c ,half of the time period has passed . ";

cout<< "\n Enter A/c No.";

cin>>acn;

for(i = 0 ; i <10 ; i++)

{

if (acn == customer[i].acno)

      customer[i].withdrw();

}

 

/* Display 10 customer's details */

for(i = 0; i<10; i++)

{

customer[i].display();

}

getch();

}